see the attached figure to better understand the problem
we know that
The volume of the cone is equal to
[tex] V=\frac{1}{3} \pi r^{2} h [/tex]
in this problem
[tex] r=\frac{6}{2} =3\ ft\\ \\ h=15\ ft [/tex]
Substitute the values in the formula above
[tex] V=\frac{1}{3}* \pi* 3^{2}* 15\\ \\ V=45\pi \ ft^{3} [/tex]
therefore
the answer is
The volume of the nose cone is [tex] 45\pi \ ft^{3} [/tex]
