What is the area of a rectangle with vertices at (−6, 3)(−6, 3) , (−3, 6)(−3, 6) , (1, 2)(1, 2) , and (−2, −1)(−2, −1) ? Do not round any side lengths.
well, find the legnth and width because lenth times width =area we just need to find 2 differnd distances
the distance between 2 points, (x1,y1) and (x2,y2) is [tex]D= \sqrt{(x2-x1)^2+(y2-y1)^2} [/tex] let's find distance between (-6,3) and (-3,6) [tex]D= \sqrt{(-3-(-6))^2+(6-3)^2} [/tex]=√18=3√2
the other one from (-3,6) to (1,2) [tex]D= \sqrt{(1-(-3))^2+(2-6)^2} [/tex]=√32=4√2
area=legnth times width legnth=4√2 width=3√2 area=4√3 times 3√2=12*2=24
