Respuesta :
basically, r=2t
A(r)=pir^2
sub 2t for r
A(2t)=pi(2t)^2
A(2t)=4pit²
A. A=4pit²
B. t=5
A=4pi5²
A=4pi25
A=100pi
A=314 square units
A(r)=pir^2
sub 2t for r
A(2t)=pi(2t)^2
A(2t)=4pit²
A. A=4pit²
B. t=5
A=4pi5²
A=4pi25
A=100pi
A=314 square units
Answer:
A: π(2t)^2 = 4πt^2
B: 4π5^2 5^2= 25x4= 100x3.14=314.
answer to B: 314(.159)
Step-by-step explanation: