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the horizontal component of a net force is 68 newtons and the angle made by the net force with the horizontal is 19., what is the value of the net force?​

Respuesta :

Trancescient

71.9 N

Explanation:

[tex] F_h = F\cos{19°} \Rightarrow F = \dfrac{F_h}{\cos{19°}}[/tex]

[tex]F = \dfrac{F_h}{\cos{19°}} = \dfrac{68\:\text{N}}{\cos{19°}}[/tex]

[tex]\:\:\:\:= 71.9\:\text{N}[/tex]

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