Respuesta :
First you calculate the area of the big rectangle (ignoring the small one the bottom):
A1 = 10 x 6 = 60.
next you calculate the small one:
A2 = 2 x 2 = 4
Now you subtract the small one from the big one and you get:
Area of the figure = A1 - A2 = 60 - 4 = 56
A1 = 10 x 6 = 60.
next you calculate the small one:
A2 = 2 x 2 = 4
Now you subtract the small one from the big one and you get:
Area of the figure = A1 - A2 = 60 - 4 = 56
To start off, pretend it's a quadrilateral. It makes everything easier and uses all the numbers.
The area of a quadrilateral is base times height.
10 = base
6 = height
6 * 10 = 60
That's the value of the original, larger, quadrilateral without the mini quadrilateral that we have to subtract.
The dimensions of the height and base of the mini quadrilateral are 2 by 2.
2 * 2 = 4
Subtract to get your answer:
60 - 4 = 56
The area of a quadrilateral is base times height.
10 = base
6 = height
6 * 10 = 60
That's the value of the original, larger, quadrilateral without the mini quadrilateral that we have to subtract.
The dimensions of the height and base of the mini quadrilateral are 2 by 2.
2 * 2 = 4
Subtract to get your answer:
60 - 4 = 56