Answer:
[tex] 4x + y +48=0[/tex]
Step-by-step explanation:
We are here given the slope of the line and one point through which it passes . The slope of the line is -4 and the point is (-9,-12) .
Here we can use the point slope form of the line as ,
[tex]\sf\longrightarrow y-y_1 = m(x-x_1) [/tex]
Substitute the respective values ,
[tex]\sf\longrightarrow y - (-12) = -4\{ x -(-9)\} [/tex]
Simplify LHS and RHS ,
[tex]\sf\longrightarrow y + 12 = -4( x +9) [/tex]
Open the brackets in RHS ,
[tex]\sf\longrightarrow y + 12 = -4x -36 [/tex]
Add 36 and 4x to both sides ,
[tex]\sf\longrightarrow \underline{\boxed{\orange{\sf 4x + y + 48 =0}}}[/tex]
