Answer:
[tex]\% Cl=61.65\%[/tex]
Explanation:
Hello,
In this case, chlorine's percent composition is given by the shown below formula:
[tex]\% Cl=\frac{n_{Cl}m_{Cl}}{M_{NaCl}}*100\%[/tex]
Whereas [tex]n_{Cl}[/tex] accounts for the number of chlorine atoms into the NaCl, [tex]m_{Cl}[/tex] for chlorine's atomic mass and [tex]M_{NaCl}[/tex] for sodium chloride's molar mass, therefore, the percent composition of chlorine turns out:
[tex]\% Cl=\frac{1*35.45}{58.45}*100\%=61.65\%[/tex]
Best regards.
