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In the given diagram, two sets of arcs are drawn above and below segment AB using a compass set to the same width. For one set of arcs, the compass needle is positioned at point A. For the second set of arcs, the compass needle is positioned at point B. A line drawn through the intersections of these two sets of arcs determines the location of point C.


Based on this construction, CB = __ units and AB = __ units.
Plz Answer ASAP! Thank you!

In the given diagram two sets of arcs are drawn above and below segment AB using a compass set to the same width For one set of arcs the compass needle is posit class=

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Answer:

Based on this construction, CB = 16  units and AB =  32

units.

Step-by-step explanation:

CB is the same number as AC, which is 16 units. They meet at the same end point, C.

AB is just AC, and CB combined. 16 + 16 = 32 units.

As per perpendicular bisector of a line, CB is 16 units and AB is 32 units.

What is a perpendicular bisector of a line?

"A perpendicular bisector is a line that bisects another line segment at a right angle, through the intersection point."

In the given diagram, the line drawn on AB and passes through the point C is the perpendicular bisector of the line AB.

Therefore, [tex]AC = CB = \frac{1}{2}AB[/tex]

Given, [tex]AC = 16[/tex] units.

Therefore, [tex]CB = 16[/tex] units.

Now,

[tex]AB\\= 2AC\\[/tex]

[tex]= 2(16)[/tex] units

[tex]= 32[/tex] units  

Learn more about the perpendicular bisector of a line here: https://brainly.com/question/24753075

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