The width of the woman's shoulder given a height of 69 inches would be 17.5 inches.
Given the parameters :
Recall ; 1 feet = 12 inches :
Setting up a proportional relationship :
[tex] \frac{64}{16.2} = \frac{69}{s} [/tex]
Cross multiply :
[tex]64s \: = 69 \times 16.2[/tex]
[tex]64s \: = 1117.8[/tex]
[tex]s \: = \frac{1117.8}{64} = 17.465 \: inches [/tex]
Therefore, the width of the woman's shoulder should be 17.5 inches.
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