Answer:
[tex]4x - 3y -3=0[/tex]
Step-by-step explanation:
Given equation ,
[tex]\implies y =\dfrac{-3}{4}x - 3 [/tex]
Compare it to slope intercept form to find the slope which is [tex]y=mx+c[/tex] , we have ,
- [tex] m =\dfrac{-3}{4}[/tex]
Now we know that the product of slope of two perpendicular lines is-1 . Hence the slope of the perpendicular line is ,
- [tex]m_{perp}= \dfrac{4}{3}[/tex]
The given point is (0,-1) , on using Point slope form of the line we have,
[tex]\implies y-y_1 = m(x - x_1) \\\\\implies y -(-1) = \dfrac{4}{3}(x -0 ) \\\\\implies y + 1 =\dfrac{4}{3}x \\\\\implies \underline{\boxed{\red{ 4x - 3y -3 = 0 }}}[/tex]
