Given the point (5, -2), and slope = 6/5
Plug in the values into the slope-intercept formula:
y = mx + b
Where:
slope (m) = 6/5
b = y-intercept
We have to solve for the y-intercept. The y-intercept is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0.
y = mx + b
-2 = 6/5(5) + b
-2 = 6 + b
Subtract 6 from both sides to solve for y-intercept, b:
-2 – 6 = b
-8 = b
Therefore, the equation of the line that passes through (5,-2) and has a slope of 6/5 is:
y = 6/5x - 8
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