Step-by-step explanation:
[tex]\textsf{\large{\underline{Solution}:}}[/tex]
Given Equations:
→ 5x - 2y = 6 ----- (i)
→ 3x + 2y = 10 ---- (ii)
Adding (i) and (ii), we get:
→ 8x = 16
→ x = 16/8
→ x = 2
Substituting the value of x in (i), we get:
→ 5 × 2 - 2y = 6
→ -2y = 6 - 10
→ -2y = -4
→ y = -4/-2
→ y = 2
Therefore:
→ (x, y) = (2, 2) (Answer)
[tex]\textsf{\large{\underline{Verification}:}}[/tex]
Put x = 2 and y = 2 in second equation, the LHS becomes:
= 5 × 2 - 2 × 2
= 10 - 4
= 6
= RHS
Put x = 2 and y = 2 in second equation, the LHS becomes:
= 3 × 2 + 2 × 2
= 6 + 4
= 10
= RHS
Hence, our answer is correct (Verified)
Hope this helps!!
