Answer:
(1)N2+3F2 -> 2NF3
Explanation:
This problem can be done a few ways.
This reaction is a redox reaction, so it will be treated as such:
First, we count the number of N atoms there are on both sides
the left has 2 and the right has 1. The LCM of 2 and 1 is 2, so the lcm of nitrogen is 2.
Similarly, the lcm of fluorine is 6, since the lcm of 2 and 3 is 6.
The LCM is also the number of atoms that there are on both sides, so there are 2 nitrogens and 6 fluorines on both sides, which isn't hard to distribute.
Here's another example:
P4 + O2 -> P2O5
lcm of 4 and 2 is 4, so there are 4 Phosphoruses on both side
Lcm of 2 and 5 is 10, so there are 10 oxygen atoms on both side
Once we know the total amount of atoms on both side, distributing them isn't very hard
(P4+5O2-> 2P2O5)
