Bhaskar went for hiking with scouts’ team and there the scouts were given a task to build tents with the help of bamboos, ropes and canvas. The frame of the tent that Bhaskar prepared was of pyramid shape. To make it sturdier Bhaskar thought that he should fix a wooden stick on the triangular sides of the tent and fix the wooden stick at the mid points of the sides of two sides of the triangle. The distance between the end point of the bamboos on the sides was 3 m. Due to lack of even length bamboo sticks Bhaskar the triangles on the edges of tent were not congruent. Look into the figure of Bhaskar’s tent and answer the following questions.
(a) To make tent sturdy Bhaskar used bamboo IJ in the back part of the tent. What length of
bamboo shall he use so that it should be fixed exactly?
(i) 9 m. (ii) 4.5 m. (iii) 3 m. (iv) 6 m
(b) Using which property of triangles Bhaskar was able to find the length of GH and IJ.
(i) Pythagoras Property. (ii) Basic Proportionality Theorem. (iii) Mid- point theorem. (iv)
Exterior angle property.
(c) How can Bhaskar find the area of canvas used only to cover the triangles?
(i) Heron’s Formula. (ii) Pythagoras Property. (iii) Area = ½ X Base X Height. (iv) Section
Formula.
(d) Here BC: EF = 3: 9, then what will be the ratio of area of triangle ABC to area of triangle DEF.
(i) 9:3 (ii) 9:81 (iii) 3.8: 11.4 (iv) 1:9