Supposing the distribution is uniform, we find that there is a 0.15 = 15% probability that a random selected occupation has an Emotional Health Index Score between 80.5 and 82.
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Uniform probability distribution:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
In this problem:
The probability between 80.5 and 82 is:
[tex]P(80.5 \leq X \leq 82) = \frac{82 - 80.5}{85 - 75} = 0.15[/tex]
0.15 = 15% probability that a random selected occupation has an Emotional Health Index Score between 80.5 and 82.
A similar problem is given at https://brainly.com/question/15855314
