The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
The molarity of the diluted solution can be obtained as follow:
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
M₂ = 1050 / 3250
Therefore, the molarity of the diluted solution is 0.32 M
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