Tanjiro48
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Can someone help me with both of the or may be one
I’m stuck on both of the question if someone could help me I would highly appreciate:)

Can someone help me with both of the or may be one Im stuck on both of the question if someone could help me I would highly appreciate class=

Respuesta :

noproblemNP

Question 6

Given:

QR = RS

QR = x + 6

RS = 4x

To find:

Length of line segment QS

Steps:

We know QR = RS, so substituting we get,

x + 6 = 4x

     6 = 4x - x

     6 = 3x

  6/3 = x

     2 = x

      x = 2

Now,

QS = QR + RS

QS = x + 6 + 4x

QS = 2 + 6 + 4(2)

QS = 2 + 6 + 8

QS = 8 + 8

QS = 16 units

Therefore, the length of QS is 16 units

Question 7

Given:

QR = RS

QR = 2x - 2

RS = 2x

To find:

Length of line segment QS

Steps:

We know that QR = RS, so substituting the values we get,

          QR = RS

      3x - 2 = 2x

3x - 2 - 2x = 0

     3x - 2x = 2

               x =2

Now,

QS = QR + RS

QS = 3x - 2 + 2x

QS = 3(2) - 2 + 2(2)

QS = 6 - 2 + 2(2)

QS = 6 - 2 + 4

QS = 4 + 4

QS = 8 units

Therefore, the length of QS is 8 units

Happy to help :)

If u need any help feel free to ask

SDCInfinity

Answer:

6.) QS = 16

7.) QS = 8

Step-by-step explanation:

The midpoint splits the segment into 2 equal segments. Therefore, set both expressions equal to each other and solve for x.

6.)

[tex]QR=RS\\\\x+6=4x\\\\x+6-x=4x-x\\\\6=3x\\\\\frac{6}{3}=\frac{3x}{3}\\\\2=x\\\\\\QR+RS=QS\\\\(2)+6+4(2)=QS\\\\16=QS[/tex]

7.)

[tex]QR=RS\\\\3x-2=2x\\\\3x-2-3x=2x-3x\\\\-2=-x\\\\\frac{-2}{-1}=\frac{-x}{-1}\\\\2=x\\\\\\QR+RS=QS\\\\3(2)-2+2(2)=QS\\\\8=QS[/tex]

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