[tex]\large \mathfrak{Solution : }[/tex]
let's solve for y :
value of y = 5
Answer:
[tex]y=5[/tex]
Step-by-step explanation:
[tex]4y=38-\frac{1}{2}\left(4y+16\right)[/tex]
→ Multiply fractions:- [tex]a\times\frac{b}{c} =\frac{a\times b}{c}[/tex]
[tex]\frac{1\cdot \left(4y+16\right)}{2}[/tex]
[tex](4y+16)=4y+16[/tex]
[tex]4y=38-\frac{4y+16}{2}[/tex]
→ Multiply both sides by 2:-
[tex]y\cdot \:2=38\cdot \:2-\frac{4y+16}{2}\cdot \:2[/tex]
[tex]8y=76-\left(4y+16\right)[/tex]
[tex]76-(4y+16)=-4x+60[/tex]
[tex]8y=-4y+60[/tex]
→ Add 4y to both sides:-
[tex]8y+4y=-4y+60+4y[/tex]
[tex]12y=60[/tex]
→ Now, divide both sides by 12:-
[tex]\frac{12y}{12}=\frac{60}{12}[/tex]
[tex]y=5[/tex]
OAmalOHopeO
