When Jason pulls a box with a force of 14 N, making a 48 angle between his arms and the horizontal, the vertical component of the force he is pulling is 10.40 N.
We can calculate the vertical component imaging a right triangle with the following dimensions:
H: is the hypotenuse = applied force (F) = 14 N (in the direction of Jason's arms)
A: is the adjacent side = horizontal component of the force
O: is the opposite side = vertical component of the force =?
θ: is the angle with the horizontal = 48°
Hence, we can find the vertical component with the following trigonometric function:
[tex] sin(\theta) = \frac{O}{H} [/tex]
[tex] O = sin(\theta)*H = sin(48)*14 N = 10.40 N [/tex]
Therefore, the vertical component of the force he is pulling is 10.40 N.
You can see more about force here: https://brainly.com/question/14131556?referrer=searchResults
I hope it helps you!
