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A rectangle has a length of 28 feet less than 10 times its width. If the area of the rectangle is 902 square feet, find the length of the rectangle.

Respuesta :

yunikawasti4

Answer:

solution

Let x = width

length = 10x-28 (28 feet less than 10 times its width)

A=l*w

A=(10x-28)

902=10x^2-28x

10x^2-28x-902=0

(10x-41) (10x+22)=0

10x-41=0

10x=41

x=41÷10

x=4.1

Now,

Length =28(4.1)-10

Therefore length =104.8

(Hope this is correct <3)

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