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A point P(3, k) is first transformed by E¹[0, 2] and then by E²[0,3/2] so that the final image is (9, 12), find the value of k.​​

A point P3 k is first transformed by E0 2 and then by E032 so that the final image is 9 12 find the value of k class=

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caylus

Hello,

The first transform E1 is the homothetie of center (0,0) and ratio=2

The second transform E2 is the homothetie of center (0,0) and ratio=3/2

P=(3,k)

P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)

P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)

==> 3k=12

k=4

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