Answer:
25.28 cm
Step-by-step explanation:
The chord is 6cm away from the centre of the circle . And the radius of the circle is 14 cm . We know that the perpendicular from the centre bisects the chord .
This will form a right angle triangle with the distance between centre and the code as its perpendicular and the length of radius as hypotenuse .
[tex]\implies Base^2+Perpendicular^2=Hypontenuse^2 \\\\\implies b^2 + (6cm)^2=(14cm)^2 \\\\\implies b^2 + 36cm^2= 196cm^2 \\\\\implies b^2 = 196cm^2-36cm^2 \\\\\implies b^2 = 160cm^2 \\\\\implies b=\sqrt{160cm^2}\\\\\implies b = 12.64 cm [/tex]
Hence the required answer is 12.64 × 2 = 25.28cm .
