Answer:
The probability that the pitcher throws exactly 8 strikes out of 15 pitches is approximately 0.199
Step-by-step explanation:
The given probability that the pitcher throws a strike, p = 0.507
The number of pitches thrown by the pitcher = 15 pitches
The probability that the pitcher does not throw a strike, q = 1 - P
∴ q = 1 - 0.507 = 0.493
By binomial theorem, we have;
[tex]P(X = r) = \dbinom{n}{r}p^{r} \cdot q^{n-r}= \dbinom{n}{r}p^{r} \cdot \left (1-p \right )^{n-r}[/tex]
When X = r = 8, and n = 15, we get;
The probability that the pitcher throws exactly 8 strikes out of 15 pitches, P(8), is given as follows
P(8) = ₁₅C₈ × 0.507⁸ × (1 - 0.507)⁽¹⁵ ⁻ ⁸⁾ = 6,435 × 0.507⁸ × 0.493⁷ ≈ 0.199
