A town has a current population of 4,000. The population increased 4 percent per year for the past four years, Emergency response professionals
make up 3 percent of the town's population.
Part A
Write a function that represents the population (p) of the town in terms of the number of years (1) for the last four years.

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conniemcarrion conniemcarrion · Answer 1 · 2021-07-14T15:52:54+02:00

Answer:

p=c(1+r)^t so the population will be 4679.43424 or rounded to 4679

Step-by-step explanation:

p=c(1+r)^t

p=4,000(1+.04)^t

p=4,000(1.04)^t

p=4,000(1.04)^4

p=4679.43424

p= the population you are solving for

c= the initial amount of the population

(1+r)= the rate of change

t= the period of time

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smecloudbird17 smecloudbird17 · Answer 2 · 2022-07-10T21:46:32+02:00

The exponential equation that represents the population of the town in terms of the number of years : [tex]p=4000 (1+0.4)^{t}[/tex]

An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.

It is similar to the amount received after investing a certain amount compounded annually.

Given,

Initial population = 4000

Rate of increase = 4%

Let current population be p.

Let number of years passed be t.

The exponential equation will be: [tex]p=4000 (1+0.4)^{t}[/tex]

(The population of the town has grown exponentially. This means that:

Initial population = 4000

Population in year I = 4000 + 4% of 4000 = 4000(1 + 0.4)

Population in year II = 4000 + 4% of 4000(1 + 0.4) = 4000(1 + 0.4)(1+0.4)

and this goes on.)

Learn more about exponential equation here

https://brainly.com/question/23729449

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