Answer:
Explanation:
[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:
[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)
KE = 450000 J
If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:
450000 = (1000)(9.8)h so
[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]
