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A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pound. If the distribution of weights for the small size packages of ground meat is approximately normally distributed, what is the best estimate of the probability that a randomly selected small size package has a weight less than 0.9 pound? Explain how you found your answer.

Respuesta :

Answer:

15.87 %

Step-by-step explanation:

z = (.9-1)/.1 = -1

z score of -1 = .1587

The probability that a randomly selected small size package has a weight of less than 0.9 pounds is 15.87 %

We have given that,

A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pounds. If the distribution of weights for the small-size packages of ground meat is approximately normally distributed

What is the formula for the z-score?

[tex]Z = \frac{x - \mu}{\sigma}[/tex]

Z = standard score

x = observed value

[tex]\mu[/tex] = mean of the sample

[tex]\sigma[/tex] = standard deviation of the sample

z = (0.9-1)/0.1 = -1

z of -1 = 0.1587

Therefore the value of the z-score is 0.1587.

To learn more about the Z-score visit:

https://brainly.com/question/25638875

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