Answer:
(2, 0) and (6, 0)
Step-by-step explanation:
[tex]y = x^2 - 8 x + 12[/tex]
To get the x intersept put y = 0
[tex]x^2 - 8 x + 12 = 0 \\\\x^2 - 6 x - 2 x + 12 = 0 \\\\x(x- 6) - 2(x - 6) = 0 \\\\(x - 2) (x - 6) = 0 \\\\x = 2 and x = 6[/tex]
So, the intersepts are
(2, 0) and (6, 0)