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Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)
The x y-coordinate plane is given.
The function enters the window in the second quadrant, goes up and right becoming less steep, crosses the y-axis at approximately y = 3.2, changes direction at the approximate point (0.7, 3.3), goes down and right becoming more steep, and stops at the closed point (2, 3).
The function starts again at the open point (2, 1), goes up and right becoming more steep, goes up and right becoming less steep, passes through the open point (4, 4), changes direction at the approximate point (4.2, 4.1), goes down and right becoming more steep, and exits the window in the first quadrant.
(a) lim x → 2− f(x)
(b) lim x → 2+ f(x)
(c) lim x → 2 f(x)
(d) f(2)
(e) lim x → 4 f(x)(f) f(4)

Respuesta :

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) [tex]\lim_{x\rightarrow 2^{-}}f(x)=3[/tex]

(b) [tex]\lim_{x\rightarrow 2^{+}}f(x)=1[/tex]

(c) [tex]\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.[/tex]

(d) [tex]f(2)=3[/tex]

(e) [tex]\lim_{x\rightarrow 4}f(x) = 4[/tex]

(f) [tex]f(4)= DNE.[/tex]{ Hole in graph}

Hence solved.

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