Hi there!
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I believe your answer is:
[tex]x = \pm 5[/tex]
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Here’s why:
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[tex]\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow \sqrt{x^2}=\sqrt{25}\\\\\rightarrow \boxed{x = \pm 5}[/tex]
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Hope this helps you. I apologize if it’s incorrect.
Answer:
[tex]x = 5 \: \: \: or \: \: \: x = - 5[/tex]
Step-by-step explanation:
[tex] {x}^{2} - 25 = 0 \\ {x}^{2} - {5}^{2} \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5[/tex]
