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Explanation:
The volume of the cone is...
V = (1/3)*pi*r^2*h
V = (1/3)*3.14*(1.25)^2*2.75
V = 4.49739583333333
which is approximate.
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The volume of the sphere is
V = (4/3)*pi*r^3
V = (4/3)*3.14*(0.25)^3 ... note the radius is half the diameter
V = 0.06541666666667
which is approximate as well
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Subtract the two volumes to finish things up
4.49739583333333-0.06541666666667 = 4.43197916666667
The result 4.43197916666667 then rounds to 4.43
This is the approximate amount of empty space in the cone that isn't taken up by the spherical gum. The units are in "cubic inches" or "in^3" for short.