Respuesta :

okpalawalter8

Answer:

[tex]\rho_s=1.07g/cc^3[/tex]

Explanation:

From the question we are told that:

Mass [tex]M=5.29g[/tex]

Volume [tex]V=5.00mL=>5.0cc^3[/tex]

Generally the equation for Specific Gravity momentum is mathematically given by

[tex]Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w[/tex]

 [tex]g=\frac{ \rho_s} { \rho_w}[/tex]

 [tex]\rho_s=\frac{ g} { \rho_w}[/tex]

 [tex]\rho_s=\frac{ 5.29} { 5}[/tex]

 [tex]\rho_s=1.07g/cc^3[/tex]

ajinems

The specific gravity of this solution is = 1.06.

Specific gravity of a solution:

The specific gravity of a solution is the mass of a unit volume of a substance to the mass of a unit volume of a given reference material.

Therefore specific gravity of the solution can be calculated as follows:

[tex]sg = \frac{density. of . substance}{density . of . water} [/tex]

But, density of substance (salt): mass/volume

mass = 5.29g

volume = 5.00mL

Therefore density = 5.29/5

= 1.06g/ml

But density of water is = 1 g/ ml

Therefore, specific gravity = 1.06/1

= 1.06

The specific gravity of a solution is 1.06.

Learn more about specific gravity here:

https://brainly.com/question/543765

Otras preguntas