The actual width of the rectangle is 24.5 meters.
The area of rectangle equals the base(width) times the height.
A = w × h
Given
Area of rectangle = 500 square meters.
Length of rectangle = 4x - 3 meters
Width of rectangle = 2x + 6 meters
Area of rectangle = length × width
500 = (4x - 3) (2x + 6)
⇒ 500 = [tex]8x^{2}+24x-6x-18[/tex]
⇒ 500 = [tex]8x^{2}+18x-18[/tex]
⇒ 500 = [tex]2(4x^{2}+9x-9)[/tex]
⇒ [tex]\frac{500}{2}=4x^{2}+9x-9[/tex]
⇒ [tex]250=4x^{2}+9x-9[/tex]
⇒ [tex]4x^{2}+9x-9-250=0[/tex]
⇒ [tex]4x^{2}+9x-259=0[/tex]
⇒ 4x(x + 7) -37(x + 7) = 0
⇒ (x + 7) (4x - 37) = 0
⇒ x = -7, x = [tex]\frac{37}{4}[/tex]
-7 is not satisfied because it is a negative number.
By substituting x = [tex]\frac{37}{4}[/tex] in width of rectangle
Actual width of rectangle = 2x + 6
= 2( [tex]\frac{37}{4}[/tex]) + 6
= [tex]\frac{37}{2}[/tex] + 6
= [tex]\frac{37+12}{2}[/tex]
= [tex]\frac{49}{2}[/tex]
= 24.5 meters
Hence, the actual width of the rectangle is 24.5 meters.
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