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The line represented by y = 3x − 2 and a line perpendicular to it intersect at R(3, 7). What is the equation of the perpendicular line? y = − negative start fraction one over three end fractionx + 4 y = − negative start fraction one over three end fractionx + 8 y = start fraction one over three end fractionx + 6 y = −3x + 7

Respuesta :

Answer:

y= -1/3(x) + 8

Step-by-step explanation:

slope of the 1st line = 3

slope of the line perpendicular to the first is its opposite reciprocal, so

slope of the 2nd line = -1/3

now we have a point and the slope of the perpendicular line, so we use the point slope formula to get:

y-7=-1/3(x-3)

y= -1/3(x) + 1 + 7

y= -1/3(x) + 8

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