Answer:
D) [tex]x^{2} =8y[/tex]
Step-by-step explanation:
Because the receiver of the parabolic dish antenna is 2 feet above the vertex, the parabola must be vertical. Therefore, we will use the equation [tex](x-h)^2=4p(y-k)[/tex] where [tex](h,k)[/tex] is the vertex of the parabola and [tex](h,k+p)[/tex] is the focus point. Since we are given that the receiver is 2 feet above the vertex which is located at the focus point and the vertex is [tex](0,0)[/tex] at the origin, then the focus point is [tex](0,0+p)[/tex] where [tex]p=2[/tex]. Therefore, the equation that models a cross section of the dish is [tex]x^{2} = 8y[/tex].
