Answer:
We reject H0 and conclude that difference ls occur in the number of Absences
Step-by-step explanation:
Given the data :
Day Monday Tuesday Wednesday Thursday Friday
Absences 37 15 12 23 43
H0: The proportions are all equal
H1: The proportions are not equal
We use the Chisquare test:
The test statistic :
χ² = Σ(observed - Expected)² / Expected
Expected value is the same for all the days, since they have the same frequency :
Expected value = percentage * sample size
Sample size = 37 + 15 + 12 + 23 + 43 = 130
Expected value = (100/5)% * 130
Expected value = 26
χ² = Σ(observed - Expected)² / Expected
χ² = (37-26)²/26 + (15-26)²/26 + (12-26)²/26 + (23-26)²/26 + (43-26)²/26
χ² = 28.31
The Pvalue using Pvalue from Chisquare test score calculator, df = 4
Pvalue = 0.000011
α = 0.05
Pvalue < α ; We reject H0 and conclude that difference ls occur in the number of Absences
