cheshirecat23
contestada

I REALLY NEED HELP WITH THIS!!!! I WILL GIVE BRAINLIEST!!!!!!!!!
Consider the equation:
3+x=x^2+3x
1) Rewrite the equation by completing the square.
Your equation should look like (x+c)^2=d or (x-c)^2=d
2) What are the solutions to the equation?

Respuesta :

Answer:

1

[tex]3 + x = {x}^{2} + 3x \\ {x}^{2} + 2x - 3 = 0 \\ ( {x}^{2} + 2x + 1) - 3 - 1 = 0 \\ {(x + 1)}^{2} - 4 = 0 \\ {(x + 1)}^{2} = 4[/tex]

2

[tex] {(x + 1)}^{2} = 4 \\ x + 1 = ±2 \\ x = 1 \: or \: - 3[/tex]

pastagobbler78

Answer:

first answer is (x+1)^2=4 and the second one is x=-1 plus or minus 2