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Use the following equation: 2Mg + O2 ā†’ 2MgO

If 20 grams of MgO were produced, and the reaction used 15 g of Mg, how much O2 was used?

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Answer:

[tex]mass \: of \: mgo \: = 20grams \\ mass \: of \: mg \: = 15grams \\ so \: from \: the \: law \: of \: conservation \: of \: mass \: = mass \: of \: o2 = (20 - 15)grams \: \\ = 5grams(ans)[/tex]

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