Answer:
0.0831 moles of NaOH were in the original mixture
Explanation:
The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.
The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.
To solve this question we must write 2 equations:
(1) 0.19mol = X + Y
Where X = Moles NaOH; Y = Moles Sr(OH)2
The moles of HCl required are:
0.100L * (2.969mol / L) = 0.2969 moles HCl
0.2969 mol = X + 2Y(2)
Replacing (1) in (2):
0.19mol - Y = X
0.2969 mol = (0.19mol - Y) + 2Y
0.1069mol = Y
Moles X = Moles NaOH:
0.19mol = X + 0.1069mol
X = 0.0831 moles of NaOH were in the original mixture
