Answer:
The required force is 475.009 KN
Explanation:
Given the data in the question;
compression strength of the concrete = 42 MPa
diameter of cylinder = 120mm
First we calculate the Area of the cylinder \;
Area of the cylinder A = [tex]\frac{\pi }{4}[/tex] × D²
we substitute
First we calculate the Area of the cylinder \;
Area of the cylinder A = [tex]\frac{\pi }{4}[/tex] × (120)²
Area of the cylinder A = [tex]\frac{\pi }{4}[/tex] × 14400
Area of the cylinder A = 11309.73355 mm²
Now, we know that;
Stress = P / A
P = Stress × A
we substitute
P = 42 × 11309.73355
P = 475008.809 N
P = ( 475008.809 × [tex]\frac{1}{1000}[/tex] )KN
P = 475.009 KN
Therefore, The required force is 475.009 KN
