Given:
The function is:
[tex]y=2x^2+3x[/tex]
Domain is the set {-2, -1, 0).
To find:
The range of the given relation.
Solution:
We have,
[tex]y=2x^2+3x[/tex]
Substituting [tex]x=-2[/tex], we get
[tex]y=2(-2)^2+3(-2)[/tex]
[tex]y=2(4)+(-6)[/tex]
[tex]y=8-6[/tex]
[tex]y=2[/tex]
Substituting [tex]x=-1[/tex], we get
[tex]y=2(-1)^2+3(-1)[/tex]
[tex]y=2(1)+(-3)[/tex]
[tex]y=2-3[/tex]
[tex]y=-1[/tex]
Substituting [tex]x=0[/tex], we get
[tex]y=2(0)^2+3(0)[/tex]
[tex]y=0+0[/tex]
[tex]y=0[/tex]
The range for the given relation is {2, -1,0}. Therefore, the correct option is (c).
