Answer:
[tex]sin A = \frac{15}{17}, \ sec A = \frac{17}8[/tex]
Step-by-step explanation:
[tex]15cot A = 8\\\\cotA = \frac{8}{15}\\\\1 + cot^2A = cosec^2 A\\\\1 + (\frac{8}{15})^2 = cosec^2 A\\\\1 + \frac{64}{225} = cosec^2A\\\\\frac{225+64}{225} = cosec^2 A\\\\cosec^2 A = \frac{289}{225}\\\\cosec A = \frac{17}{15}\\\\That \ is, \ \frac{1}{sin A} = \frac{17}{15}\\\\sin A = \frac{15}{17}[/tex]
[tex]cot A = \frac{8}{15}\\\\\frac{cos A}{sinA} = \frac{8}{15}\\\\cos A = \frac{8}{15} \times sin A = \frac{8}{15} \times \frac{15}{17} = \frac{8}{17}\\\\\frac{1}{cosA} = \frac{17}{8}\\\\sec A = \frac{17}{8}[/tex]
