Respuesta :

facundo3141592

Answer:

We have:

x = t^2 + 2*t

y = -t

where:

–4 ≤ t ≤ 1

Isolating t in the "y" equation, we get:

t = -y

Now we can use the limits of t, to find similar limits for y.

When t = -4

-4 = -y

4 = y

when t = 1

1 = -y

-1 = y

Then the limits for y are:

-1 < y < 4

Now, knowing that t = -y

we can replace that in the "x" equation:

x = t^2 + 2*t

x = (-y)^2 + 2*(-y)

x = y^2 - 2*y

Then the graph of the parametric equation is the one defined by:

x = y^2 - 2*y

in the range

-1 < y < 4

The graph of this can be seen below, where the two black dots are the points where the graph should start/end.

Ver imagen facundo3141592
xero099

The graph that represents the parametric equations is a parabola with an axis of symmetry is parallel to the x-axis.

An approach to determine the possible graph consists in eliminating [tex]t[/tex] and simplify the resulting expression of the form [tex]f(x)[/tex]:

[tex]x = t^{2}+2\cdot t[/tex] (1)

[tex]y = -t[/tex] (2)

By (2):

[tex]t = -y[/tex]

(2) in (1):

[tex]x = (-y)^{2} + 2\cdot (-y)[/tex]

[tex]x = y^{2}-2\cdot y[/tex]

In a nutshell, the graph that represents the parametric equations is a parabola with an axis of symmetry is parallel to the x-axis.

To learn more on parametric equations, we kindly invite to check this verified question: https://brainly.com/question/9056657

Ver imagen xero099

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