Answer:
The theoretical probability that the spinner below lands on the letter B is 1/2
Step-by-step explanation:
Given
[tex]S =\{A,B,B,B,C,C\}[/tex]
[tex]n(S) = 6[/tex]
See attachment for spinner
Required
P(B)
From the attached spinner, we have:
[tex]n(B) = 3[/tex] --- occurrence of B
So:
[tex]P(B) = \frac{n(B)}{n(S)}[/tex]
[tex]P(B) = \frac{3}{6}[/tex]
[tex]P(B) = 1/2[/tex]
