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Explanation:
For now, let's focus on the probability of getting one "5".
There are 4 of these cards (one of each suit) and 52 total. The probability of getting the card we're after is 4/52 = 1/13.
We can think of it like saying "if we focus on one suit only, then there's a 1 in 13 chance of getting a '5' from this pile".
The probability of getting two "5"s in a row is (1/13)*(1/13) = 1/169 assuming we put the first card back. If the first card is not put back, then we would compute it like so: (4/52)*(3/51). I'll leave it unevaluated for you to try out as practice.
Side note: 1/169 = 0.0059 = 0.59% approximately