Answer:
Thus, the horizontal range is 17.7 m, and the maximum height is 10.2 m.
Explanation:
velocity of projection, v = 20 m/s
Angle of projection, A = 30 degree
The horizontal range is
[tex]R =\frac{v^{2}sin2A}{g}\\R=\frac{20\times 20\times sin60}{2\times 9.8}\\R=17.7 m[/tex]
The maximum height is
[tex]H =\frac{v^{2}sin^{2}A}{2g}\\H=\frac{20\times 20\times sin^{2}30}{9.8}\\H=10.2 m[/tex]
