The dimensions for the width and height of the fish tank will be 4 feet and 2 feet .
Dimension is the measurable extent of a particular kind, such as length, breadth, depth, or height.
According to the given problem,
let , b = is the width of the fish tank
h = is the height of the fish tank given that , hold at least 35 cubic feet of water .
so ,
4×b×h ≥ 35
⇒ h ≥ 35/4b
now , surface area of the fish tank
⇒ 4b + 2× 4h + 2× bh
now substitute the value of h
here
⇒ ≥ 4b +70/b + 35/2
⇒ ≥ 40(70)^1/2 + 35/2 (if and only if b= (70)^1/2 / 2 , the equal sign holds )
therefore ,
= (70)^1/2 / 2 b ≈ 4.18 so b is 4 . when b = 4 ,
h = 35 / 4 × 4 = 2.1875 round off h = 2
so , the minimum surface area of fish tank is
⇒ 4×4+ 2× 4×2 + 2× 4×2⇒ 48
hence , the height and the width of the fish tank is 2 and 4 .
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