Answer:
The battery is charging and has a current of 2Amps passing through.
Explanation:
Given;
EMF of the battery, E = 12 V
internal resistance, r = 0.5 ohms
terminal voltage of the battery, ΔV = 13 volts
When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.
ΔV = E - Ir
ΔV - E = -Ir
13 - 12 = -0.5I
1 = -0.5I
I = 1 / -0.5
I = -2 A
The negative sign indicates the reverse direction of the current.
Therefore, the battery is charging and has a current of 2Amps passing through.