Respuesta :
Answer:
[tex]\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}[/tex]
General Formulas and Concepts:
Pre-Algebra
Distributive Property
Algebra I
- Factoring
Calculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Trig Differentiation
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Implicit Differentiation
Step-by-step explanation:
Step 1: Define
Identify
sin(x) + cos(y) + sec(xy) = 251
Step 2: Differentiate
- [Implicit Differentiation] Trig Differentiation [Chain Rule]: [tex]\displaystyle cos(x) - sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = 0[/tex]
- [Subtraction Property of Equality] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] terms: [tex]\displaystyle -sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = -cos(x)[/tex]
- [Distributive Property] Distribute sec(xy)tan(xy): [tex]\displaystyle -sin(y)\frac{dy}{dx} + ysec(xy)tan(xy) + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x)[/tex]
- [Subtraction Property of Equality] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] terms: [tex]\displaystyle -sin(y)\frac{dy}{dx} + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x) - ysec(xy)tan(xy)[/tex]
- Factor out [tex]\displaystyle \frac{dy}{dx}[/tex]: [tex]\displaystyle \frac{dy}{dx}[-sin(y) + xsec(xy)tan(xy)] = -cos(x) - ysec(xy)tan(xy)[/tex]
- [Division Property of Equality] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex]: [tex]\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}[/tex]
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Implicit Differentiation
Book: College Calculus 10e