Answer:
The required value of [tex]x[/tex] is [tex]\frac{3}{5}[/tex]
Step-by-step explanation:
Given,
f (2) = 60 – 5
= (30 X 2) - 5
∴ f (x) = [tex]30x-5[/tex]
Again,
f (x) = 13 [given]
[tex]30x-5=13\\or, 30x= 13+5\\or, 30x=18\\or, x=\frac{18}{30} \\\\or, x=\frac{3}{5} \\[/tex]
∴[tex]x=\frac{3}{5}[/tex]
Verification:
f (x) = [tex]30x-5[/tex]
∴ f ([tex]\frac{3}{5}[/tex]) = (30 X [tex]\frac{3}{5}[/tex]) - 5
= 18 - 5
= 13
∴ The required value of [tex]x[/tex] is [tex]\frac{3}{5}[/tex]
