Answer:
[tex]144.9\leq x\leq 145.5[/tex]
Step-by-step explanation:
Let x represent actual weight of object.
We have been that the weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 lbs.
[tex]|\text{Actual}-\text{Ideal}|\leq \text{Tolerance}[/tex].
Upon substituting our given values, we will get:
[tex]|x-145.2|\leq 0.3[/tex]
Applying absolute value rule [tex]|u|\leq a=-a\leq u\leq a[/tex], we will get:
[tex]-0.3\leq x-145.2\leq 0.3[/tex]
Add 145.2 on each side:
[tex]-0.3+145.2\leq x-145.2+145.2\leq 0.3+145.2[/tex]
[tex]144.9\leq x\leq 145.5[/tex]
Therefore, our required range will be [tex]144.9\leq x\leq 145.5[/tex].
